2g-9=g^2-8g+16

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Solution for 2g-9=g^2-8g+16 equation: 



2g-9=g^2-8g+16

We move all terms to the left:

2g-9-(g^2-8g+16)=0

We get rid of parentheses

-g^2+2g+8g-16-9=0

We add all the numbers together, and all the variables

-1g^2+10g-25=0

a = -1; b = 10; c = -25;
Δ = b2-4ac
Δ = 102-4·(-1)·(-25)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$g=\frac{-b}{2a}=\frac{-10}{-2}=+5$

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